Type 2 Position Of Hands Of The Clock Practice Questions Answers Test With Solutions & More Shortcuts

Answer: (c)

Time period from 1 O' clock afternoon to 10 O' clock night = (10 - 1)h = 9 h

As we know, hands are at right angle 2 times in an hour.

Hence, in 9 h they will be at right angle 9 × 2 = 18 times

Answer: (a)

Answer: (c)

At 4 O' clock, hour hand is at 4 and minute hand is at 12.

To be together with hour hand minute hand will have to gain 20 min. As 55 min are gained by minute hand in 60 min.

Therefore, 20 min will be gained in $(60/55 × 20)$ min = $(60 × 4/11)$ min = $240 / 11$ min

= 21 $9/11$ min Hence, the hands will be together at 21 $9/11$ min past 4.

Answer: (b)

The hands of a clock are in the same straight line (but opposite in direction) 11 times in every 12 h, because between 5 and 7 they point in opposite direction at 6 O' clock only.

Therefore, in a day (24 h) the hands points in the opposite direction (2 × 11) = 22 times.

Answer: (d)

We know that the hands of a clock are at right angle twice in every hour but between 2 and 4 O' clock there is a common position at 3 O' clock and also between 8 and 10 O' clock there is common position at 9 O' clock.

So, they are at right angles 22 times in 12 h and therefore, in 24 h or in a day they are at right angle 44 times.